The next time you posture down to tackle a jigsaw puzzle , bring your calculator – you just might need it .

Math kind of has a repute for being a dry issue , suitable only for boffins and … uh … FBI agent ? But the truth is , mathematicians are fun , cool people , who enjoymaximally effective partiesandhumorous wordplayjust like the rest of us .

And what ’s the most badass thing a person can do ? That ’s correct : scroll saw . So it ’s no curiosity that mathematician have turned their care to the pursuit , offer up an answer to the question plaguing puzzlers the world over : on the button how large of a mesa do you call for to put your ‘ sawing machine on ?

A diagram showing circles packing in a hexagonal packing arrangement.

Circles packed in a hexagonal packing arrangement.Image Credit: Inductiveload, Public domain, viaWikimedia Commons

Well , okay – technically , it was n’t mathematician , rather one biophysicist and one experimental quantum physicist . “ My husband and I were doing a jigsaw puzzle one Clarence Day , ” Madeleine Bonsma - Fisher , a postdoc at the University of Toronto , toldNew Scientist , “ and I just enquire if you could estimate the area that the musical composition take up before you put the puzzle together . ”

The resolution : a neat little newspaper , barely six Page long , which takes the construct of optimalcircle packingand applies it to your grandma ’s favourite rainy - twenty-four hours natural action . ( It ’s worth noting that while only a preprint , and therefore not peer - look back , the geometry calculations used in the paper are pretty basic and unlikely to be incorrect . )

“ citizenry have been concerned in coiffure circles in 2D for a long time , ” Bonsma - Fisher toldPopular Mechanics , “ and it ’s now known that format circles in a hexangular grille is the tightest potential way of life to arrange them on a 2D surface , where the goal is to have the belittled space possible between circles . ”

![The Mona Lisa rendered in squares, showing that each square is of length (area of puzzle)/(number of pieces) and the diagonal d](https://assets.iflscience.com/assets/articleNo/72753/iImg/73918/image (5).png)

Pythagoras’s Theorem states that a^2 + b^2 = c^2 … or in this case, d^2.Image Credit: Leonardo Da Vinci, Public Domain, Edited By IFLScience

“ This is also the reason why honeycombs are shaped the direction they are , ” she pointed out . “ [ B]ees actually make circular cells , but these get squished into ahexagonal lattice , [ which is ] the most efficient way to slop circles together . ”

The thought is this : for a table to curb every piece of a jigsaw puzzle , it should be bragging enough to correspond that figure of circle across it . That might vocalize strange – after all , saber saw pieces are generallynotcircular – but there ’s a method in the madness : the Bonsma - Fishers are looking not for the out-and-out minimal area needed to correspond all pieces , but “ the area the pieces take up when you do n’t bear much attention to while preference or billet , ” she explained .

It ’s less efficient , quad - wise , but it makes more sentience for a human puzzle - solver . By count each piece as a circle rather than some closer idea , there ’s way for us to revolve , move , or swap out various pieces – and in reality , y’know , solve the thing .

![Workings shown: area of disassembled puzzle is equal to root(3) times area of assembled puzzle.](https://assets.iflscience.com/assets/articleNo/72753/iImg/73888/Screenshot 2024-02-02 020501.png)

For those taking notes.Image Credit: IFLScience

So , what ’s the answer ? Well , it pretty much comes down to that hexagonal tiling approach pattern . If we tie it out , we can see that each hexagon has an area approximately three times that of one orbitual “ teaser spell ” – there ’s the all over one in the middle , and then six thirds around the bound .

Now , the area of a regular hexagon is 3√3/2 timesd2 , wheredis the length of the sides . So what’sd ? Well , we can see from the diagram that it ’s the diam of one of the circles – or , in teaser piece footing , the diagonal across one piece .

Assuming each man is ( roughly ) a lame , then , thatdwill be the hypotenuse of a right - angled triangle with two adequate shorter sides of length √(Area of full mystifier / Number of puzzle pieces ) . Using the Pythagorean theorem , this means thatd2is equal to twice the area of the puzzle separate by the number of part .

The full amount of space needed , then , is adequate to the number of piecesNtimes the area of one piece . That art object , if you remember , is approximately one - third of the area of one hexagon in this lattice shape – which , in twist , is adequate to 3√3/2 timesd2 . In other Word of God ,

The final result : stem 3 . “ The country of the unassembled puzzle is just √3 meter the area of the assembled puzzle , main of the number of piece , ” write the Bonsma - Fishers in their paper .

Just to make indisputable , the couple control their formula on nine puzzles , ranging from a 9 - opus to a 2000 - objet d’art . It worked perfectly : “ We found close correspondence between realistic measure and our theoretical prognostication across a wide range of mystifier arena and numbers of pieces , ” the pair wrote , before stage photographic grounds of a completed 1008 - composition jigsaw puzzle .

So , now we know : if you need enough space for all your jigsaw patch , ensure your surface is about 1.73 time the country of your mystifier – although “ if you really want to lie all your piece out insipid and be well-situated , ” Bonsma - Fisher told New Scientist , “ your table should be a little over twice as prominent as your sample puzzle . ”

The newspaper can be encounter on theArXiV.